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THERE IS NO TRICK ANSWER!
These are the items you will be working with. 8 baseballs and a scale
One of the baseballs is slightly lighter ( or heavier doesn't matter). Use the scale least amount of times possible to find the odd ball. How many times did you use the scale and explain your answer.
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The complete step-by-step guide to get back to selling today!
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HeeHee. | 
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I like the shiny plates on the scale - that`s money $
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3 Times
(1) Weigh 4 Balls vs 4 Balls---Eliminate the lighter set of 4
(2) of the 4 Balls left weigh 2 Balls vs 2 Balls---Eliminate the lighter set of 2
(3) Weigh the 2 Remaining balls against each other---Eliminate the lighter Ball,,and Your left with the heavyest ball
------------------------------
Thats how I would do it
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Place three balls on each side.
If the scales are balanced then weight the remaining two balls to find the odd ball.
If the scales are tipped then remove one ball from each side and replace with the unweighed balls. Swap a ball with each side which was on the scale during the first weigh.
You are now able to determine the odd ball and you've only used the scales twice.
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Twice is the answer.
Make two groups of 3 and one group of 2 balls.
If the scales balance then the heavy ball is one of the two left over.
Weigh the two balls and the heavier ball with drop the scales therefore you will then know which ball is the heaviest one.
Or you can do it in reverse to find the lighter weighing ball.
Nice to add the grass stained practice ball to make you think...... | 
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Originally Posted by mine Place three balls on each side.
If the scales are balanced then weight the remaining two balls to find the odd ball.
If the scales are tipped then remove one ball from each side and replace with the unweighed balls. Swap a ball with each side which was on the scale during the first weigh.
You are now able to determine the odd ball and you've only used the scales twice. | Sorry mine I cant seem to understand your answer
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Originally Posted by slapped 3 Times
(1) Weigh 4 Balls vs 4 Balls---Eliminate the lighter set of 4
(2) of the 4 Balls left weigh 2 Balls vs 2 Balls---Eliminate the lighter set of 2
(3) Weigh the 2 Remaining balls against each other---Eliminate the lighter Ball,,and Your left with the heavyest ball
------------------------------
Thats how I would do it | That's how id do it too, but there is a shorter way!
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Originally Posted by Sandy D Twice is the answer.
Make two groups of 3 and one group of 2 balls.
If the scales balance then the heavy ball is one of the two left over.
Weigh the two balls and the heavier ball with drop the scales therefore you will then know which ball is the heaviest one.
Or you can do it in reverse to find the lighter weighing ball.
Nice to add the grass stained practice ball to make you think......  | lol about the pictures, I looked on google and wrote 8 balls and thats what popped up, then not to confuse ppl too much on top of page I wrote not a trick question.
""""""So what happens if the scale is not balanced when weighing 3 on 3 ?""""""
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Also check this one out guys....... THIS IS SOMETHING EVERYONE SHOULD KNOW!!! To many mistakes done daily and never knowing. http://www.aspkin.com/forums/everyth...tml#post449009
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Here is where I got my lesson in HIGHER Mathamatics:
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Originally Posted by AllAboutStealth Sorry mine I cant seem to understand your answer | It reads pretty clear to me. What part don't you understand?
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Originally Posted by slapped | Slapped thats an awesome video!
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Originally Posted by mine Place three balls on each side.
If the scales are balanced then weight the remaining two balls to find the odd ball.
If the scales are tipped then remove one ball from each side and replace with the unweighed balls. Swap a ball with each side which was on the scale during the first weigh.
You are now able to determine the odd ball and you've only used the scales twice. | "Place three balls on each side.
If the scales are balanced then weight the remaining two balls to find the odd ball."
This much I understood perfectly
Now the rest I understood, "If the scales are tipped(uneven) then remove one ball from each side and replace with the unweighed(the two balls that we didnt weight) balls."
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Originally Posted by AllAboutStealth lol about the pictures, I looked on google and wrote 8 balls and thats what popped up, then not to confuse ppl too much on top of page I wrote not a trick question.
""""""So what happens if the scale is not balanced when weighing 3 on 3 ?"""""" |
Then Simply Discard the 3 Lighter weighting Balls, Then, select 2 of the 3 Remaining Balls and weigh the 2 of them against each other, if One is Heavier then you have your anwser on the scales if they are both the same then the heavest ball is NOT on the scale,,,
I had to watch that Abbot and Costello Math lesson to figure it out,,,oh and By the way if you ever want to know a little about Baseball:,,,
This Skit is actually in Baseballs Hall of Fame...
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Originally Posted by slapped Then Simply Discard the 3 Lighter weighting Balls, Then, select 2 of the 3 Remaining Balls and weigh the 2 of them against each other, if One is Heavier then you have your anwser on the scales if they are both the same then the heavest ball is NOT on the scale,,,
I had to watch that Abbot and Costello Math lesson to figure it out,,,oh and By the way if you ever want to know a little about Baseball:,,, Who's on first? - YouTube
This Skit is actually in Baseballs Hall of Fame... |      the video gave me a good laugh, thnx
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Originally Posted by AllAboutStealth "Place three balls on each side.
If the scales are balanced then weight the remaining two balls to find the odd ball."
This much I understood perfectly
Now the rest I understood, "If the scales are tipped(uneven) then remove one ball from each side and replace with the unweighed(the two balls that we didnt weight) balls." | Then just swap a ball on each side with each other. The idea is you should have only one ball left on each side that has not moved since the first wiegh. That means if the scales tip the same way then the odd ball is that one which has not been moved. If the scale tips the other way then it's the ball you swapped. And if the scales are balanced then it was the ball you took off.
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Originally Posted by mine Then just swap a ball on each side with each other. The idea is you should have only one ball left on each side that has not moved since the first wiegh. That means if the scales tip the same way then the odd ball is that one which has not been moved. If the scale tips the other way then it's the ball you swapped. And if the scales are balanced then it was the ball you took off. | That could take more then 2 tries
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Life's mysteries | 
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okkkkkkkkkkk here we go, rule of thumb is, if you post a riddle thing... and don't really know the 100% true answer.
don't post.
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Originally Posted by golden_monkey okkkkkkkkkkk here we go, rule of thumb is, if you post a riddle thing... and don't really know the 100% true answer.
don't post. |
Where did you come from?
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