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  #1  
Old 05-12-2013
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Default Solve the puzzle!

THERE IS NO TRICK ANSWER!

These are the items you will be working with. 8 baseballs and a scale


One of the baseballs is slightly lighter ( or heavier doesn't matter). Use the scale least amount of times possible to find the odd ball. How many times did you use the scale and explain your answer.
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HeeHee.


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Old 05-12-2013
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I like the shiny plates on the scale - that`s money $
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Old 05-12-2013
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3 Times
(1) Weigh 4 Balls vs 4 Balls---Eliminate the lighter set of 4
(2) of the 4 Balls left weigh 2 Balls vs 2 Balls---Eliminate the lighter set of 2
(3) Weigh the 2 Remaining balls against each other---Eliminate the lighter Ball,,and Your left with the heavyest ball
------------------------------

Thats how I would do it
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Last edited by slapped; 05-12-2013 at 11:21 PM.
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Old 05-13-2013
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Place three balls on each side.

If the scales are balanced then weight the remaining two balls to find the odd ball.

If the scales are tipped then remove one ball from each side and replace with the unweighed balls. Swap a ball with each side which was on the scale during the first weigh.

You are now able to determine the odd ball and you've only used the scales twice.
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Old 05-13-2013
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Twice is the answer.

Make two groups of 3 and one group of 2 balls.

If the scales balance then the heavy ball is one of the two left over.

Weigh the two balls and the heavier ball with drop the scales therefore you will then know which ball is the heaviest one.

Or you can do it in reverse to find the lighter weighing ball.



Nice to add the grass stained practice ball to make you think......
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Old 05-13-2013
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Quote:
Originally Posted by mine View Post
Place three balls on each side.

If the scales are balanced then weight the remaining two balls to find the odd ball.

If the scales are tipped then remove one ball from each side and replace with the unweighed balls. Swap a ball with each side which was on the scale during the first weigh.

You are now able to determine the odd ball and you've only used the scales twice.
Sorry mine I cant seem to understand your answer
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Old 05-13-2013
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Quote:
Originally Posted by slapped View Post
3 Times
(1) Weigh 4 Balls vs 4 Balls---Eliminate the lighter set of 4
(2) of the 4 Balls left weigh 2 Balls vs 2 Balls---Eliminate the lighter set of 2
(3) Weigh the 2 Remaining balls against each other---Eliminate the lighter Ball,,and Your left with the heavyest ball
------------------------------

Thats how I would do it
That's how id do it too, but there is a shorter way!
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Originally Posted by Sandy D View Post
Twice is the answer.

Make two groups of 3 and one group of 2 balls.

If the scales balance then the heavy ball is one of the two left over.

Weigh the two balls and the heavier ball with drop the scales therefore you will then know which ball is the heaviest one.

Or you can do it in reverse to find the lighter weighing ball.



Nice to add the grass stained practice ball to make you think......
lol about the pictures, I looked on google and wrote 8 balls and thats what popped up, then not to confuse ppl too much on top of page I wrote not a trick question.

""""""So what happens if the scale is not balanced when weighing 3 on 3 ?""""""
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Last edited by AllAboutStealth; 05-13-2013 at 02:19 PM.
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Old 05-13-2013
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Also check this one out guys....... THIS IS SOMETHING EVERYONE SHOULD KNOW!!! To many mistakes done daily and never knowing.

http://www.aspkin.com/forums/everyth...tml#post449009
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Here is where I got my lesson in HIGHER Mathamatics:

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Last edited by slapped; 05-13-2013 at 11:12 PM.
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Old 05-14-2013
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dogmath.jpg

Higher math.
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Quote:
Originally Posted by AllAboutStealth View Post
Sorry mine I cant seem to understand your answer
It reads pretty clear to me. What part don't you understand?
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Old 05-14-2013
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Quote:
Originally Posted by slapped View Post
Here is where I got my lesson in HIGHER Mathamatics:

Abbott And Costello 13 X 7 is 28 - YouTube
Slapped thats an awesome video!
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  #15  
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Quote:
Originally Posted by mine View Post
Place three balls on each side.

If the scales are balanced then weight the remaining two balls to find the odd ball.

If the scales are tipped then remove one ball from each side and replace with the unweighed balls. Swap a ball with each side which was on the scale during the first weigh.

You are now able to determine the odd ball and you've only used the scales twice.
"Place three balls on each side.

If the scales are balanced then weight the remaining two balls to find the odd ball."

This much I understood perfectly

Now the rest I understood, "If the scales are tipped(uneven) then remove one ball from each side and replace with the unweighed(the two balls that we didnt weight) balls."
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Old 05-15-2013
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Quote:
Originally Posted by AllAboutStealth View Post
lol about the pictures, I looked on google and wrote 8 balls and thats what popped up, then not to confuse ppl too much on top of page I wrote not a trick question.

""""""So what happens if the scale is not balanced when weighing 3 on 3 ?""""""



Then Simply Discard the 3 Lighter weighting Balls, Then, select 2 of the 3 Remaining Balls and weigh the 2 of them against each other, if One is Heavier then you have your anwser on the scales if they are both the same then the heavest ball is NOT on the scale,,,



I had to watch that Abbot and Costello Math lesson to figure it out,,,oh and By the way if you ever want to know a little about Baseball:,,,





This Skit is actually in Baseballs Hall of Fame...
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Old 05-16-2013
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Quote:
Originally Posted by slapped View Post
Then Simply Discard the 3 Lighter weighting Balls, Then, select 2 of the 3 Remaining Balls and weigh the 2 of them against each other, if One is Heavier then you have your anwser on the scales if they are both the same then the heavest ball is NOT on the scale,,,



I had to watch that Abbot and Costello Math lesson to figure it out,,,oh and By the way if you ever want to know a little about Baseball:,,,




Who's on first? - YouTube

This Skit is actually in Baseballs Hall of Fame...
the video gave me a good laugh, thnx
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Quote:
Originally Posted by AllAboutStealth View Post
"Place three balls on each side.

If the scales are balanced then weight the remaining two balls to find the odd ball."

This much I understood perfectly

Now the rest I understood, "If the scales are tipped(uneven) then remove one ball from each side and replace with the unweighed(the two balls that we didnt weight) balls."
Then just swap a ball on each side with each other. The idea is you should have only one ball left on each side that has not moved since the first wiegh. That means if the scales tip the same way then the odd ball is that one which has not been moved. If the scale tips the other way then it's the ball you swapped. And if the scales are balanced then it was the ball you took off.
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Then just swap a ball on each side with each other. The idea is you should have only one ball left on each side that has not moved since the first wiegh. That means if the scales tip the same way then the odd ball is that one which has not been moved. If the scale tips the other way then it's the ball you swapped. And if the scales are balanced then it was the ball you took off.
That could take more then 2 tries
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Old 05-16-2013
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Life's mysteries


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okkkkkkkkkkk here we go, rule of thumb is, if you post a riddle thing... and don't really know the 100% true answer.

don't post.
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Originally Posted by golden_monkey View Post
okkkkkkkkkkk here we go, rule of thumb is, if you post a riddle thing... and don't really know the 100% true answer.

don't post.

Where did you come from?
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